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10^x*9^x=1000
We move all terms to the left:
10^x*9^x-(1000)=0
Wy multiply elements
90x^2-1000=0
a = 90; b = 0; c = -1000;
Δ = b2-4ac
Δ = 02-4·90·(-1000)
Δ = 360000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{360000}=600$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-600}{2*90}=\frac{-600}{180} =-3+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+600}{2*90}=\frac{600}{180} =3+1/3 $
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